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\left(a+7c\right)\left(a^{2}-7ac+49c^{2}\right)
Rewrite a^{3}+343c^{3} as a^{3}+\left(7c\right)^{3}. The sum of cubes can be factored using the rule: p^{3}+q^{3}=\left(p+q\right)\left(p^{2}-pq+q^{2}\right).