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\left(am^{2}n^{3}-12\right)\left(am^{2}n^{3}+12\right)
Rewrite a^{2}m^{4}n^{6}-144 as \left(am^{2}n^{3}\right)^{2}-12^{2}. The difference of squares can be factored using the rule: p^{2}-q^{2}=\left(p-q\right)\left(p+q\right).