Solve a^{2}bc^5[(-2b^3c^2)*(b^3c)]

$$a ^ { 2 } b c ^ { 5 } [ ( - 2 b ^ { 3 } c ^ { 2 } ) \cdot ( b ^ { 3 } c ) ]$$

Evaluate

$$-2a^{2}b^{7}c^{8}$$

Solution Steps

To multiply powers of the same base, add their exponents. Add 1 and 3 to get 4.

$$a^{2}b^{4}c^{5}\left(-2\right)c^{2}b^{3}c$$

To multiply powers of the same base, add their exponents. Add 4 and 3 to get 7.

$$a^{2}b^{7}c^{5}\left(-2\right)c^{2}c$$

To multiply powers of the same base, add their exponents. Add 5 and 2 to get 7.

$$a^{2}b^{7}c^{7}\left(-2\right)c$$

To multiply powers of the same base, add their exponents. Add 7 and 1 to get 8.

$$a^{2}b^{7}c^{8}\left(-2\right)$$

Differentiate w.r.t. a

$$-4ab^{7}c^{8}$$