Solve a^2-ba^a-140=0

$$a ^ { 2 } - b a ^ { a } - 140 = 0$$

Solve for b (complex solution)

$$b=\frac{a^{2}-140}{a^{a}}$$

Steps for Solving Linear Equation

Add 140 to both sides. Anything plus zero gives itself.

$$a^{2}-ba^{a}=140$$

Subtract a^{2} from both sides.

$$-ba^{a}=140-a^{2}$$

The equation is in standard form.

$$\left(-a^{a}\right)b=140-a^{2}$$

Divide both sides by -a^{a}.

$$\frac{\left(-a^{a}\right)b}{-a^{a}}=\frac{140-a^{2}}{-a^{a}}$$

Dividing by -a^{a} undoes the multiplication by -a^{a}.

$$b=\frac{140-a^{2}}{-a^{a}}$$

Divide -a^{2}+140 by -a^{a}.

$$b=a^{2-a}-\frac{140}{a^{a}}$$

Solve for b

$$b=\frac{a^{2}-140}{a^{a}}$$

$$\left(a<0\text{ and }Denominator(a)\text{bmod}2=1\right)\text{ or }a>0$$

Steps for Solving Linear Equation

Add 140 to both sides. Anything plus zero gives itself.

$$a^{2}-ba^{a}=140$$

Subtract a^{2} from both sides.

$$-ba^{a}=140-a^{2}$$

The equation is in standard form.

$$\left(-a^{a}\right)b=140-a^{2}$$

Divide both sides by -a^{a}.

$$\frac{\left(-a^{a}\right)b}{-a^{a}}=\frac{140-a^{2}}{-a^{a}}$$

Dividing by -a^{a} undoes the multiplication by -a^{a}.

$$b=\frac{140-a^{2}}{-a^{a}}$$

Divide 140-a^{2} by -a^{a}.

$$b=a^{2-a}-\frac{140}{a^{a}}$$