Solve a^2-8x+5=0

$$a ^ { 2 } - 8 x + 5 = 0$$

Solve for x

$$x=\frac{a^{2}+5}{8}$$

Steps for Solving Linear Equation

Subtract a^{2} from both sides. Anything subtracted from zero gives its negation.

$$-8x+5=-a^{2}$$

Subtract 5 from both sides.

$$-8x=-a^{2}-5$$

Divide both sides by -8.

$$\frac{-8x}{-8}=\frac{-a^{2}-5}{-8}$$

Dividing by -8 undoes the multiplication by -8.

$$x=\frac{-a^{2}-5}{-8}$$

Divide -a^{2}-5 by -8.

$$x=\frac{a^{2}+5}{8}$$

Solve for a (complex solution)

$$a=-\sqrt{8x-5}$$

$$a=\sqrt{8x-5}$$

Solve for a

$$a=\sqrt{8x-5}$$

$$a=-\sqrt{8x-5}\text{, }x\geq \frac{5}{8}$$