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a\left(a-2\right)=0
Factor out a.
a=0 a=2
To find equation solutions, solve a=0 and a-2=0.
a^{2}-2a=0
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
a=\frac{-\left(-2\right)±\sqrt{\left(-2\right)^{2}}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, -2 for b, and 0 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
a=\frac{-\left(-2\right)±2}{2}
Take the square root of \left(-2\right)^{2}.
a=\frac{2±2}{2}
The opposite of -2 is 2.
a=\frac{4}{2}
Now solve the equation a=\frac{2±2}{2} when ± is plus. Add 2 to 2.
a=2
Divide 4 by 2.
a=\frac{0}{2}
Now solve the equation a=\frac{2±2}{2} when ± is minus. Subtract 2 from 2.
a=0
Divide 0 by 2.
a=2 a=0
The equation is now solved.
a^{2}-2a=0
Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.
a^{2}-2a+1=1
Divide -2, the coefficient of the x term, by 2 to get -1. Then add the square of -1 to both sides of the equation. This step makes the left hand side of the equation a perfect square.
\left(a-1\right)^{2}=1
Factor a^{2}-2a+1. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(a-1\right)^{2}}=\sqrt{1}
Take the square root of both sides of the equation.
a-1=1 a-1=-1
Simplify.
a=2 a=0
Add 1 to both sides of the equation.