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\frac{9a^{2}-b^{2}}{9}
Factor out \frac{1}{9}.
\left(3a-b\right)\left(3a+b\right)
Consider 9a^{2}-b^{2}. Rewrite 9a^{2}-b^{2} as \left(3a\right)^{2}-b^{2}. The difference of squares can be factored using the rule: p^{2}-q^{2}=\left(p-q\right)\left(p+q\right).
\frac{\left(3a-b\right)\left(3a+b\right)}{9}
Rewrite the complete factored expression.