Factor
\frac{\left(5a-1\right)\left(5a+1\right)}{25}
Evaluate
a^{2}-\frac{1}{25}
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\frac{25a^{2}-1}{25}
Factor out \frac{1}{25}.
\left(5a-1\right)\left(5a+1\right)
Consider 25a^{2}-1. Rewrite 25a^{2}-1 as \left(5a\right)^{2}-1^{2}. The difference of squares can be factored using the rule: p^{2}-q^{2}=\left(p-q\right)\left(p+q\right).
\frac{\left(5a-1\right)\left(5a+1\right)}{25}
Rewrite the complete factored expression.
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