Solve a^2*a^4+(-a^2)^3=

$$a ^ { 2 } \cdot a ^ { 4 } + ( - a ^ { 2 } ) ^ { 3 } =$$

Evaluate

$$0$$

Solution Steps

To multiply powers of the same base, add their exponents. Add 2 and 4 to get 6.

$$a^{6}+\left(-a^{2}\right)^{3}$$

Expand \left(-a^{2}\right)^{3}.

$$a^{6}+\left(-1\right)^{3}\left(a^{2}\right)^{3}$$

To raise a power to another power, multiply the exponents. Multiply 2 and 3 to get 6.

$$a^{6}+\left(-1\right)^{3}a^{6}$$

Calculate -1 to the power of 3 and get -1.

$$a^{6}-a^{6}$$

Combine a^{6} and -a^{6} to get 0.

$$0$$

Factor

$$0$$