Solve a^2*4x+4=0

$$a ^ { 2 } \cdot 4 x + 4 = 0$$

Solve for x

$$x=-\frac{1}{a^{2}}$$

$$a\neq 0$$

Steps for Solving Linear Equation

Subtract 4 from both sides. Anything subtracted from zero gives its negation.

$$a^{2}\times 4x=-4$$

The equation is in standard form.

$$4a^{2}x=-4$$

Divide both sides by 4a^{2}.

$$\frac{4a^{2}x}{4a^{2}}=-\frac{4}{4a^{2}}$$

Dividing by 4a^{2} undoes the multiplication by 4a^{2}.

$$x=-\frac{4}{4a^{2}}$$

Divide -4 by 4a^{2}.

$$x=-\frac{1}{a^{2}}$$

Solve for a (complex solution)

$$a=-ix^{-\frac{1}{2}}$$

$$a=ix^{-\frac{1}{2}}\text{, }x\neq 0$$

Solve for a

$$a=\sqrt{-\frac{1}{x}}$$

$$a=-\sqrt{-\frac{1}{x}}\text{, }x<0$$