Solve a^2=104

$$a ^ { 2 } = 104$$

Solve for a

$$a=2\sqrt{26}\approx 10.198039027$$

$$a=-2\sqrt{26}\approx -10.198039027$$

Steps by Finding Square Root

Take the square root of both sides of the equation.

$$a=2\sqrt{26} a=-2\sqrt{26}$$

Steps Using the Quadratic Formula

Subtract 104 from both sides.

$$a^{2}-104=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -104 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$a=\frac{0±\sqrt{0^{2}-4\left(-104\right)}}{2}$$

Square 0.

$$a=\frac{0±\sqrt{-4\left(-104\right)}}{2}$$

Multiply -4 times -104.

$$a=\frac{0±\sqrt{416}}{2}$$

Take the square root of 416.

$$a=\frac{0±4\sqrt{26}}{2}$$

Now solve the equation a=\frac{0±4\sqrt{26}}{2} when ± is plus.

$$a=2\sqrt{26}$$

Now solve the equation a=\frac{0±4\sqrt{26}}{2} when ± is minus.

$$a=-2\sqrt{26}$$

The equation is now solved.

$$a=2\sqrt{26} a=-2\sqrt{26}$$