Solve a^2+4^2=8^2

$$a ^ { 2 } + 4 ^ { 2 } = 8 ^ { 2 }$$

Solve for a

$$a=4\sqrt{3}\approx 6.92820323$$

$$a=-4\sqrt{3}\approx -6.92820323$$

Steps by Finding Square Root

Calculate 4 to the power of 2 and get 16.

$$a^{2}+16=8^{2}$$

Calculate 8 to the power of 2 and get 64.

$$a^{2}+16=64$$

Subtract 16 from both sides.

$$a^{2}=64-16$$

Subtract 16 from 64 to get 48.

$$a^{2}=48$$

Take the square root of both sides of the equation.

$$a=4\sqrt{3} a=-4\sqrt{3}$$

Steps Using the Quadratic Formula

Calculate 4 to the power of 2 and get 16.

$$a^{2}+16=8^{2}$$

Calculate 8 to the power of 2 and get 64.

$$a^{2}+16=64$$

Subtract 64 from both sides.

$$a^{2}+16-64=0$$

Subtract 64 from 16 to get -48.

$$a^{2}-48=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -48 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$a=\frac{0±\sqrt{0^{2}-4\left(-48\right)}}{2}$$

Square 0.

$$a=\frac{0±\sqrt{-4\left(-48\right)}}{2}$$

Multiply -4 times -48.

$$a=\frac{0±\sqrt{192}}{2}$$

Take the square root of 192.

$$a=\frac{0±8\sqrt{3}}{2}$$

Now solve the equation a=\frac{0±8\sqrt{3}}{2} when ± is plus.

$$a=4\sqrt{3}$$

Now solve the equation a=\frac{0±8\sqrt{3}}{2} when ± is minus.

$$a=-4\sqrt{3}$$

The equation is now solved.

$$a=4\sqrt{3} a=-4\sqrt{3}$$