Solve a^2+2b+17=6

$$a ^ { 2 } + 2 b + 17 = 6$$

Solve for b

$$b=\frac{-a^{2}-11}{2}$$

Steps for Solving Linear Equation

Subtract a^{2} from both sides.

$$2b+17=6-a^{2}$$

Subtract 17 from both sides.

$$2b=6-a^{2}-17$$

Subtract 17 from 6 to get -11.

$$2b=-11-a^{2}$$

The equation is in standard form.

$$2b=-a^{2}-11$$

Divide both sides by 2.

$$\frac{2b}{2}=\frac{-a^{2}-11}{2}$$

Dividing by 2 undoes the multiplication by 2.

$$b=\frac{-a^{2}-11}{2}$$

Solve for a (complex solution)

$$a=-\sqrt{-2b-11}$$

$$a=\sqrt{-2b-11}$$

Solve for a

$$a=\sqrt{-2b-11}$$

$$a=-\sqrt{-2b-11}\text{, }b\leq -\frac{11}{2}$$