Solve a^2+2ab+6^2

$$a ^ { 2 } + 2 a b + 6 ^ { 2 }$$

Differentiate w.r.t. a

$$2\left(a+b\right)$$

Steps Using Derivative Rule for Sum

Calculate 6 to the power of 2 and get 36.

$$\frac{\mathrm{d}}{\mathrm{d}a}(a^{2}+2ab+36)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$2a^{2-1}+2ba^{1-1}$$

Subtract 1 from 2.

$$2a^{1}+2ba^{1-1}$$

Subtract 1 from 1.

$$2a^{1}+2ba^{0}$$

For any term t, t^{1}=t.

$$2a+2ba^{0}$$

For any term t except 0, t^{0}=1.

$$2a+2b\times 1$$

For any term t, t\times 1=t and 1t=t.

$$2a+2b$$

Evaluate

$$a^{2}+2ab+36$$

Solution Steps

Calculate 6 to the power of 2 and get 36.

$$a^{2}+2ab+36$$