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\left(a^{4}-3b\right)\left(a^{8}+9b^{2}+3ba^{4}\right)
Rewrite a^{12}-27b^{3} as \left(a^{4}\right)^{3}-\left(3b\right)^{3}. The difference of cubes can be factored using the rule: p^{3}-q^{3}=\left(p-q\right)\left(p^{2}+pq+q^{2}\right).