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\left(a^{5}-7b^{6}\right)\left(a^{5}+7b^{6}\right)
Rewrite a^{10}-49b^{12} as \left(a^{5}\right)^{2}-\left(7b^{6}\right)^{2}. The difference of squares can be factored using the rule: p^{2}-q^{2}=\left(p-q\right)\left(p+q\right).