Solve for b (complex solution)
\left\{\begin{matrix}b=\frac{a+c}{x}\text{, }&x\neq 0\\b\in \mathrm{C}\text{, }&a=-c\text{ and }x=0\end{matrix}\right.
Solve for b
\left\{\begin{matrix}b=\frac{a+c}{x}\text{, }&x\neq 0\\b\in \mathrm{R}\text{, }&a=-c\text{ and }x=0\end{matrix}\right.
Solve for a
a=bx-c
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bx-c=a
Swap sides so that all variable terms are on the left hand side.
bx=a+c
Add c to both sides.
xb=a+c
The equation is in standard form.
\frac{xb}{x}=\frac{a+c}{x}
Divide both sides by x.
b=\frac{a+c}{x}
Dividing by x undoes the multiplication by x.
bx-c=a
Swap sides so that all variable terms are on the left hand side.
bx=a+c
Add c to both sides.
xb=a+c
The equation is in standard form.
\frac{xb}{x}=\frac{a+c}{x}
Divide both sides by x.
b=\frac{a+c}{x}
Dividing by x undoes the multiplication by x.
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