Solve a=8-4/s+1

$$a = 8 - \frac { 4 } { s + 1 }$$

Solve for s

$$s=-\frac{a-4}{a-8}$$

$$a\neq 8$$

Steps for Solving Linear Equation

Variable s cannot be equal to -1 since division by zero is not defined. Multiply both sides of the equation by s+1.

$$a\left(s+1\right)=\left(s+1\right)\times 8-4$$

Use the distributive property to multiply a by s+1.

$$as+a=\left(s+1\right)\times 8-4$$

Use the distributive property to multiply s+1 by 8.

$$as+a=8s+8-4$$

Subtract 4 from 8 to get 4.

$$as+a=8s+4$$

Subtract 8s from both sides.

$$as+a-8s=4$$

Subtract a from both sides.

$$as-8s=4-a$$

Combine all terms containing s.

$$\left(a-8\right)s=4-a$$

Divide both sides by a-8.

$$\frac{\left(a-8\right)s}{a-8}=\frac{4-a}{a-8}$$

Dividing by a-8 undoes the multiplication by a-8.

$$s=\frac{4-a}{a-8}$$

Variable s cannot be equal to -1.

$$s=\frac{4-a}{a-8}\text{, }s\neq -1$$

Solve for a

$$a=\frac{4\left(2s+1\right)}{s+1}$$

$$s\neq -1$$