Solve a=4b-3ab

$$a = 4 b - 3 a b$$

Solve for a

$$a=\frac{4b}{3b+1}$$

$$b\neq -\frac{1}{3}$$

Steps for Solving Linear Equation

Add 3ab to both sides.

$$a+3ab=4b$$

Combine all terms containing a.

$$\left(1+3b\right)a=4b$$

The equation is in standard form.

$$\left(3b+1\right)a=4b$$

Divide both sides by 3b+1.

$$\frac{\left(3b+1\right)a}{3b+1}=\frac{4b}{3b+1}$$

Dividing by 3b+1 undoes the multiplication by 3b+1.

$$a=\frac{4b}{3b+1}$$

Solve for b

$$b=\frac{a}{4-3a}$$

$$a\neq \frac{4}{3}$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$4b-3ab=a$$

Combine all terms containing b.

$$\left(4-3a\right)b=a$$

Divide both sides by 4-3a.

$$\frac{\left(4-3a\right)b}{4-3a}=\frac{a}{4-3a}$$

Dividing by 4-3a undoes the multiplication by 4-3a.

$$b=\frac{a}{4-3a}$$