Solve a=(1-1/3)^3*(3/2)^-1:(2/9)^4

$$a = ( 1 - \frac { 1 } { 3 } ) ^ { 3 } \times ( \frac { 3 } { 2 } ) ^ { - 1 } : ( \frac { 2 } { 9 } ) ^ { 4 }$$

Solve for a

$$a=81$$

Steps for Solving Linear Equation

Subtract \frac{1}{3} from 1 to get \frac{2}{3}.

$$a=\frac{\left(\frac{2}{3}\right)^{3}\times \left(\frac{3}{2}\right)^{-1}}{\left(\frac{2}{9}\right)^{4}}$$

Calculate \frac{2}{3} to the power of 3 and get \frac{8}{27}.

$$a=\frac{\frac{8}{27}\times \left(\frac{3}{2}\right)^{-1}}{\left(\frac{2}{9}\right)^{4}}$$

Calculate \frac{3}{2} to the power of -1 and get \frac{2}{3}.

$$a=\frac{\frac{8}{27}\times \frac{2}{3}}{\left(\frac{2}{9}\right)^{4}}$$

Multiply \frac{8}{27} and \frac{2}{3} to get \frac{16}{81}.

$$a=\frac{\frac{16}{81}}{\left(\frac{2}{9}\right)^{4}}$$

Calculate \frac{2}{9} to the power of 4 and get \frac{16}{6561}.

$$a=\frac{\frac{16}{81}}{\frac{16}{6561}}$$

Divide \frac{16}{81} by \frac{16}{6561} by multiplying \frac{16}{81} by the reciprocal of \frac{16}{6561}.

$$a=\frac{16}{81}\times \frac{6561}{16}$$

Multiply \frac{16}{81} and \frac{6561}{16} to get 81.

$$a=81$$

Assign a

$$a≔81$$