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Solve for a (complex solution)
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Solve for a
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Solve for b (complex solution)
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Solve for b
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a-\frac{bcx-3ax}{4}=0
Subtract \frac{bcx-3ax}{4} from both sides.
4a-\left(bcx-3ax\right)=0
Multiply both sides of the equation by 4.
4a-bcx+3ax=0
To find the opposite of bcx-3ax, find the opposite of each term.
4a+3ax=bcx
Add bcx to both sides. Anything plus zero gives itself.
\left(4+3x\right)a=bcx
Combine all terms containing a.
\left(3x+4\right)a=bcx
The equation is in standard form.
\frac{\left(3x+4\right)a}{3x+4}=\frac{bcx}{3x+4}
Divide both sides by 4+3x.
a=\frac{bcx}{3x+4}
Dividing by 4+3x undoes the multiplication by 4+3x.
a-\frac{bcx-3ax}{4}=0
Subtract \frac{bcx-3ax}{4} from both sides.
4a-\left(bcx-3ax\right)=0
Multiply both sides of the equation by 4.
4a-bcx+3ax=0
To find the opposite of bcx-3ax, find the opposite of each term.
4a+3ax=bcx
Add bcx to both sides. Anything plus zero gives itself.
\left(4+3x\right)a=bcx
Combine all terms containing a.
\left(3x+4\right)a=bcx
The equation is in standard form.
\frac{\left(3x+4\right)a}{3x+4}=\frac{bcx}{3x+4}
Divide both sides by 4+3x.
a=\frac{bcx}{3x+4}
Dividing by 4+3x undoes the multiplication by 4+3x.