Solve a=2b+4/3c-5

$$a = \frac { 2 b + 4 } { 3 c - 5 }$$

Solve for b

$$b=\frac{3ac}{2}-\frac{5a}{2}-2$$

$$c\neq \frac{5}{3}$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 3c-5.

$$a\left(3c-5\right)=2b+4$$

Use the distributive property to multiply a by 3c-5.

$$3ac-5a=2b+4$$

Swap sides so that all variable terms are on the left hand side.

$$2b+4=3ac-5a$$

Subtract 4 from both sides.

$$2b=3ac-5a-4$$

Divide both sides by 2.

$$\frac{2b}{2}=\frac{3ac-5a-4}{2}$$

Dividing by 2 undoes the multiplication by 2.

$$b=\frac{3ac-5a-4}{2}$$

Divide 3ac-5a-4 by 2.

$$b=\frac{3ac}{2}-\frac{5a}{2}-2$$

Solve for a

$$a=\frac{2\left(b+2\right)}{3c-5}$$

$$c\neq \frac{5}{3}$$