Solve for a
a=-\frac{b-25}{b+1}
b\neq -1
Solve for b
b=-\frac{a-25}{a+1}
a\neq -1
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a+ab=25-b
Subtract b from both sides.
\left(1+b\right)a=25-b
Combine all terms containing a.
\left(b+1\right)a=25-b
The equation is in standard form.
\frac{\left(b+1\right)a}{b+1}=\frac{25-b}{b+1}
Divide both sides by 1+b.
a=\frac{25-b}{b+1}
Dividing by 1+b undoes the multiplication by 1+b.
b+ab=25-a
Subtract a from both sides.
\left(1+a\right)b=25-a
Combine all terms containing b.
\left(a+1\right)b=25-a
The equation is in standard form.
\frac{\left(a+1\right)b}{a+1}=\frac{25-a}{a+1}
Divide both sides by 1+a.
b=\frac{25-a}{a+1}
Dividing by 1+a undoes the multiplication by 1+a.
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