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\left(1+r\right)a=\frac{8}{3}
Combine all terms containing a.
\left(r+1\right)a=\frac{8}{3}
The equation is in standard form.
\frac{\left(r+1\right)a}{r+1}=\frac{\frac{8}{3}}{r+1}
Divide both sides by 1+r.
a=\frac{\frac{8}{3}}{r+1}
Dividing by 1+r undoes the multiplication by 1+r.
a=\frac{8}{3\left(r+1\right)}
Divide \frac{8}{3} by 1+r.
ar=\frac{8}{3}-a
Subtract a from both sides.
\frac{ar}{a}=\frac{\frac{8}{3}-a}{a}
Divide both sides by a.
r=\frac{\frac{8}{3}-a}{a}
Dividing by a undoes the multiplication by a.
r=-1+\frac{8}{3a}
Divide \frac{8}{3}-a by a.