Solve for a
a=28-2c-4b
Solve for b
b=-\frac{a}{4}-\frac{c}{2}+7
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a+2c=28-4b
Subtract 4b from both sides.
a=28-4b-2c
Subtract 2c from both sides.
4b+2c=28-a
Subtract a from both sides.
4b=28-a-2c
Subtract 2c from both sides.
4b=28-2c-a
The equation is in standard form.
\frac{4b}{4}=\frac{28-2c-a}{4}
Divide both sides by 4.
b=\frac{28-2c-a}{4}
Dividing by 4 undoes the multiplication by 4.
b=-\frac{a}{4}-\frac{c}{2}+7
Divide 28-a-2c by 4.
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