Solve a+4ab-3ab=6ab+4b

$$a + 4 a b - 3 a b = 6 a b + 4 b$$

Solve for a

$$a=\frac{4b}{1-5b}$$

$$b\neq \frac{1}{5}$$

Steps for Solving Linear Equation

Combine 4ab and -3ab to get ab.

$$a+ab=6ab+4b$$

Subtract 6ab from both sides.

$$a+ab-6ab=4b$$

Combine ab and -6ab to get -5ab.

$$a-5ab=4b$$

Combine all terms containing a.

$$\left(1-5b\right)a=4b$$

Divide both sides by -5b+1.

$$\frac{\left(1-5b\right)a}{1-5b}=\frac{4b}{1-5b}$$

Dividing by -5b+1 undoes the multiplication by -5b+1.

$$a=\frac{4b}{1-5b}$$

Solve for b

$$b=\frac{a}{5a+4}$$

$$a\neq -\frac{4}{5}$$

Steps for Solving Linear Equation

Combine 4ab and -3ab to get ab.

$$a+ab=6ab+4b$$

Subtract 6ab from both sides.

$$a+ab-6ab=4b$$

Combine ab and -6ab to get -5ab.

$$a-5ab=4b$$

Subtract 4b from both sides.

$$a-5ab-4b=0$$

Subtract a from both sides. Anything subtracted from zero gives its negation.

$$-5ab-4b=-a$$

Combine all terms containing b.

$$\left(-5a-4\right)b=-a$$

Divide both sides by -4-5a.

$$\frac{\left(-5a-4\right)b}{-5a-4}=-\frac{a}{-5a-4}$$

Dividing by -4-5a undoes the multiplication by -4-5a.

$$b=-\frac{a}{-5a-4}$$

Divide -a by -4-5a.

$$b=\frac{a}{5a+4}$$