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aa+a\times 4=3+a\times 4
Variable a cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by a.
a^{2}+a\times 4=3+a\times 4
Multiply a and a to get a^{2}.
a^{2}+a\times 4-a\times 4=3
Subtract a\times 4 from both sides.
a^{2}=3
Combine a\times 4 and -a\times 4 to get 0.
a=\sqrt{3} a=-\sqrt{3}
Take the square root of both sides of the equation.
aa+a\times 4=3+a\times 4
Variable a cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by a.
a^{2}+a\times 4=3+a\times 4
Multiply a and a to get a^{2}.
a^{2}+a\times 4-3=a\times 4
Subtract 3 from both sides.
a^{2}+a\times 4-3-a\times 4=0
Subtract a\times 4 from both sides.
a^{2}-3=0
Combine a\times 4 and -a\times 4 to get 0.
a=\frac{0±\sqrt{0^{2}-4\left(-3\right)}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -3 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
a=\frac{0±\sqrt{-4\left(-3\right)}}{2}
Square 0.
a=\frac{0±\sqrt{12}}{2}
Multiply -4 times -3.
a=\frac{0±2\sqrt{3}}{2}
Take the square root of 12.
a=\sqrt{3}
Now solve the equation a=\frac{0±2\sqrt{3}}{2} when ± is plus.
a=-\sqrt{3}
Now solve the equation a=\frac{0±2\sqrt{3}}{2} when ± is minus.
a=\sqrt{3} a=-\sqrt{3}
The equation is now solved.