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X\left(X-2\right)\leq 0
Factor out X.
X\geq 0 X-2\leq 0
For the product to be ≤0, one of the values X and X-2 has to be ≥0 and the other has to be ≤0. Consider the case when X\geq 0 and X-2\leq 0.
X\in \begin{bmatrix}0,2\end{bmatrix}
The solution satisfying both inequalities is X\in \left[0,2\right].
X-2\geq 0 X\leq 0
Consider the case when X\leq 0 and X-2\geq 0.
X\in \emptyset
This is false for any X.
X\in \begin{bmatrix}0,2\end{bmatrix}
The final solution is the union of the obtained solutions.