Solve V_{m}=2-5m/2m+1

$$V _ { m } = \frac { 2 - 5 m } { 2 m + 1 }$$

Solve for m

$$m=-\frac{V_{m}-2}{2V_{m}+5}$$

$$V_{m}\neq -\frac{5}{2}$$

Steps for Solving Linear Equation

Variable m cannot be equal to -\frac{1}{2} since division by zero is not defined. Multiply both sides of the equation by 2m+1.

$$V_{m}\left(2m+1\right)=2-5m$$

Use the distributive property to multiply V_{m} by 2m+1.

$$2V_{m}m+V_{m}=2-5m$$

Add 5m to both sides.

$$2V_{m}m+V_{m}+5m=2$$

Subtract V_{m} from both sides.

$$2V_{m}m+5m=2-V_{m}$$

Combine all terms containing m.

$$\left(2V_{m}+5\right)m=2-V_{m}$$

Divide both sides by 2V_{m}+5.

$$\frac{\left(2V_{m}+5\right)m}{2V_{m}+5}=\frac{2-V_{m}}{2V_{m}+5}$$

Dividing by 2V_{m}+5 undoes the multiplication by 2V_{m}+5.

$$m=\frac{2-V_{m}}{2V_{m}+5}$$

Variable m cannot be equal to -\frac{1}{2}.

$$m=\frac{2-V_{m}}{2V_{m}+5}\text{, }m\neq -\frac{1}{2}$$

Solve for V_m

$$V_{m}=-\frac{5m-2}{2m+1}$$

$$m\neq -\frac{1}{2}$$