Solve V_1^2-1.3*1.3=-0.6*10*2*0.13

$$V _ { 1 } ^ { 2 } - 1.3 \times 1.3 = - 0.6 \times 10 \times 2 \times 0.13$$

Solve for V_1

$$V_{1}=\frac{\sqrt{13}}{10}\approx 0.360555128$$

$$V_{1}=-\frac{\sqrt{13}}{10}\approx -0.360555128$$

Steps by Finding Square Root

Multiply 1.3 and 1.3 to get 1.69.

$$V_{1}^{2}-1.69=-0.6\times 10\times 2\times 0.13$$

Multiply -0.6 and 10 to get -6.

$$V_{1}^{2}-1.69=-6\times 2\times 0.13$$

Multiply -6 and 2 to get -12.

$$V_{1}^{2}-1.69=-12\times 0.13$$

Multiply -12 and 0.13 to get -1.56.

$$V_{1}^{2}-1.69=-1.56$$

Add 1.69 to both sides.

$$V_{1}^{2}=-1.56+1.69$$

Add -1.56 and 1.69 to get 0.13.

$$V_{1}^{2}=0.13$$

Take the square root of both sides of the equation.

$$V_{1}=\frac{\sqrt{13}}{10} V_{1}=-\frac{\sqrt{13}}{10}$$

Steps Using the Quadratic Formula

Multiply 1.3 and 1.3 to get 1.69.

$$V_{1}^{2}-1.69=-0.6\times 10\times 2\times 0.13$$

Multiply -0.6 and 10 to get -6.

$$V_{1}^{2}-1.69=-6\times 2\times 0.13$$

Multiply -6 and 2 to get -12.

$$V_{1}^{2}-1.69=-12\times 0.13$$

Multiply -12 and 0.13 to get -1.56.

$$V_{1}^{2}-1.69=-1.56$$

Add 1.56 to both sides.

$$V_{1}^{2}-1.69+1.56=0$$

Add -1.69 and 1.56 to get -0.13.

$$V_{1}^{2}-0.13=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -0.13 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$V_{1}=\frac{0±\sqrt{0^{2}-4\left(-0.13\right)}}{2}$$

Square 0.

$$V_{1}=\frac{0±\sqrt{-4\left(-0.13\right)}}{2}$$

Multiply -4 times -0.13.

$$V_{1}=\frac{0±\sqrt{0.52}}{2}$$

Take the square root of 0.52.

$$V_{1}=\frac{0±\frac{\sqrt{13}}{5}}{2}$$

Now solve the equation V_{1}=\frac{0±\frac{\sqrt{13}}{5}}{2} when ± is plus.

$$V_{1}=\frac{\sqrt{13}}{10}$$

Now solve the equation V_{1}=\frac{0±\frac{\sqrt{13}}{5}}{2} when ± is minus.

$$V_{1}=-\frac{\sqrt{13}}{10}$$

The equation is now solved.

$$V_{1}=\frac{\sqrt{13}}{10} V_{1}=-\frac{\sqrt{13}}{10}$$