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V^{2}-1024=0
Subtract 1024 from both sides.
\left(V-32\right)\left(V+32\right)=0
Consider V^{2}-1024. Rewrite V^{2}-1024 as V^{2}-32^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).
V=32 V=-32
To find equation solutions, solve V-32=0 and V+32=0.
V=32 V=-32
Take the square root of both sides of the equation.
V^{2}-1024=0
Subtract 1024 from both sides.
V=\frac{0±\sqrt{0^{2}-4\left(-1024\right)}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -1024 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
V=\frac{0±\sqrt{-4\left(-1024\right)}}{2}
Square 0.
V=\frac{0±\sqrt{4096}}{2}
Multiply -4 times -1024.
V=\frac{0±64}{2}
Take the square root of 4096.
V=32
Now solve the equation V=\frac{0±64}{2} when ± is plus. Divide 64 by 2.
V=-32
Now solve the equation V=\frac{0±64}{2} when ± is minus. Divide -64 by 2.
V=32 V=-32
The equation is now solved.