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Solve for N
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V=\pi k^{2}N-\frac{1}{9}\pi k^{3}
Use the distributive property to multiply \frac{1}{9}\pi k^{2} by 9N-k.
\pi k^{2}N-\frac{1}{9}\pi k^{3}=V
Swap sides so that all variable terms are on the left hand side.
\pi k^{2}N=V+\frac{1}{9}\pi k^{3}
Add \frac{1}{9}\pi k^{3} to both sides.
\pi k^{2}N=\frac{\pi k^{3}}{9}+V
The equation is in standard form.
\frac{\pi k^{2}N}{\pi k^{2}}=\frac{\frac{\pi k^{3}}{9}+V}{\pi k^{2}}
Divide both sides by \pi k^{2}.
N=\frac{\frac{\pi k^{3}}{9}+V}{\pi k^{2}}
Dividing by \pi k^{2} undoes the multiplication by \pi k^{2}.
N=\frac{k}{9}+\frac{V}{\pi k^{2}}
Divide V+\frac{\pi k^{3}}{9} by \pi k^{2}.