Solve V=1.25*(1+T/R)

$$V = 1.25 \times (1+ \frac{ T }{ R } )$$

Solve for T

$$T=\frac{R\left(4V-5\right)}{5}$$

$$R\neq 0$$

Steps for Solving Linear Equation

Multiply both sides of the equation by R.

$$VR=1.25\left(1+\frac{T}{R}\right)R$$

To add or subtract expressions, expand them to make their denominators the same. Multiply 1 times \frac{R}{R}.

$$VR=1.25\left(\frac{R}{R}+\frac{T}{R}\right)R$$

Since \frac{R}{R} and \frac{T}{R} have the same denominator, add them by adding their numerators.

$$VR=1.25\times \frac{R+T}{R}R$$

Express \frac{R+T}{R}R as a single fraction.

$$VR=1.25\times \frac{\left(R+T\right)R}{R}$$

Cancel out R in both numerator and denominator.

$$VR=1.25\left(R+T\right)$$

Use the distributive property to multiply 1.25 by R+T.

$$VR=1.25R+1.25T$$

Swap sides so that all variable terms are on the left hand side.

$$1.25R+1.25T=VR$$

Subtract 1.25R from both sides.

$$1.25T=VR-1.25R$$

The equation is in standard form.

$$\frac{5}{4}T=RV-\frac{5R}{4}$$

Divide both sides of the equation by \frac{5}{4}, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{\frac{5}{4}T}{\frac{5}{4}}=\frac{R\left(V-1.25\right)}{\frac{5}{4}}$$

Dividing by \frac{5}{4} undoes the multiplication by \frac{5}{4}.

$$T=\frac{R\left(V-1.25\right)}{\frac{5}{4}}$$

Divide R\left(-1.25+V\right) by \frac{5}{4} by multiplying R\left(-1.25+V\right) by the reciprocal of \frac{5}{4}.

$$T=\frac{4R\left(V-1.25\right)}{5}$$

Solve for R

$$\left\{\begin{matrix}\\R\neq 0\text{, }&\text{unconditionally}\\R=-\frac{5T}{5-4V}\text{, }&T\neq 0\text{ and }V\neq \frac{5}{4}\end{matrix}\right.$$