Solve for k (complex solution)
\left\{\begin{matrix}k=\frac{2U}{x^{2}}\text{, }&x\neq 0\\k\in \mathrm{C}\text{, }&U=0\text{ and }x=0\end{matrix}\right.
Solve for k
\left\{\begin{matrix}k=\frac{2U}{x^{2}}\text{, }&x\neq 0\\k\in \mathrm{R}\text{, }&U=0\text{ and }x=0\end{matrix}\right.
Solve for U
U=\frac{kx^{2}}{2}
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\frac{1}{2}kx^{2}=U
Swap sides so that all variable terms are on the left hand side.
\frac{x^{2}}{2}k=U
The equation is in standard form.
\frac{2\times \frac{x^{2}}{2}k}{x^{2}}=\frac{2U}{x^{2}}
Divide both sides by \frac{1}{2}x^{2}.
k=\frac{2U}{x^{2}}
Dividing by \frac{1}{2}x^{2} undoes the multiplication by \frac{1}{2}x^{2}.
\frac{1}{2}kx^{2}=U
Swap sides so that all variable terms are on the left hand side.
\frac{x^{2}}{2}k=U
The equation is in standard form.
\frac{2\times \frac{x^{2}}{2}k}{x^{2}}=\frac{2U}{x^{2}}
Divide both sides by \frac{1}{2}x^{2}.
k=\frac{2U}{x^{2}}
Dividing by \frac{1}{2}x^{2} undoes the multiplication by \frac{1}{2}x^{2}.
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