Solve T_{2}=1520mm*290^circK/380mm

$$T _ { 2 } = \frac { 1520 mm \times 290 ^ { \circ } K } { 380 mm }$$

Solve for K

$$K=\frac{T_{2}}{1160}$$

$$m\neq 0$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 380m^{2}.

$$T_{2}\times 380m^{2}=1520mm\times 290K$$

Multiply m and m to get m^{2}.

$$T_{2}\times 380m^{2}=1520m^{2}\times 290K$$

Multiply 1520 and 290 to get 440800.

$$T_{2}\times 380m^{2}=440800m^{2}K$$

Swap sides so that all variable terms are on the left hand side.

$$440800m^{2}K=T_{2}\times 380m^{2}$$

The equation is in standard form.

$$440800m^{2}K=380T_{2}m^{2}$$

Divide both sides by 440800m^{2}.

$$\frac{440800m^{2}K}{440800m^{2}}=\frac{380T_{2}m^{2}}{440800m^{2}}$$

Dividing by 440800m^{2} undoes the multiplication by 440800m^{2}.

$$K=\frac{380T_{2}m^{2}}{440800m^{2}}$$

Divide 380T_{2}m^{2} by 440800m^{2}.

$$K=\frac{T_{2}}{1160}$$

Solve for T_2

$$T_{2}=1160K$$

$$m\neq 0$$

Solution Steps

Multiply m and m to get m^{2}.

$$T_{2}=\frac{1520m^{2}\times 290K}{380mm}$$

Multiply m and m to get m^{2}.

$$T_{2}=\frac{1520m^{2}\times 290K}{380m^{2}}$$

Cancel out 380m^{2} in both numerator and denominator.

$$T_{2}=4\times 290K$$

Multiply 4 and 290 to get 1160.

$$T_{2}=1160K$$