Solve T_{2}=1.520mm*290^circK/380mm

$$T _ { 2 } = \frac { 1.520 mm \times 290 ^ { \circ } K } { 380 mm }$$

Solve for K

$$K=\frac{25T_{2}}{29}$$

$$m\neq 0$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 380m^{2}.

$$T_{2}\times 380m^{2}=1.52mm\times 290K$$

Multiply m and m to get m^{2}.

$$T_{2}\times 380m^{2}=1.52m^{2}\times 290K$$

Multiply 1.52 and 290 to get 440.8.

$$T_{2}\times 380m^{2}=440.8m^{2}K$$

Swap sides so that all variable terms are on the left hand side.

$$440.8m^{2}K=T_{2}\times 380m^{2}$$

The equation is in standard form.

$$\frac{2204m^{2}}{5}K=380T_{2}m^{2}$$

Divide both sides by 440.8m^{2}.

$$\frac{5\times \frac{2204m^{2}}{5}K}{2204m^{2}}=\frac{5\times 380T_{2}m^{2}}{2204m^{2}}$$

Dividing by 440.8m^{2} undoes the multiplication by 440.8m^{2}.

$$K=\frac{5\times 380T_{2}m^{2}}{2204m^{2}}$$

Divide 380T_{2}m^{2} by 440.8m^{2}.

$$K=\frac{25T_{2}}{29}$$

Solve for T_2

$$T_{2}=\frac{29K}{25}$$

$$m\neq 0$$

Solution Steps

Multiply m and m to get m^{2}.

$$T_{2}=\frac{1.52m^{2}\times 290K}{380mm}$$

Multiply m and m to get m^{2}.

$$T_{2}=\frac{1.52m^{2}\times 290K}{380m^{2}}$$

Cancel out 10m^{2} in both numerator and denominator.

$$T_{2}=\frac{1.52\times 29K}{38}$$

Multiply 1.52 and 29 to get 44.08.

$$T_{2}=\frac{44.08K}{38}$$

Divide 44.08K by 38 to get 1.16K.

$$T_{2}=1.16K$$