Solve TI=5*7/(4+7)*(4+3)

$$T I = \frac { 5 \times 7 } { ( 4 + 7 ) \times ( 4 + 3 ) }$$

Solve for I

$$I=\frac{5}{11T}$$

$$T\neq 0$$

Steps for Solving Linear Equation

Multiply 5 and 7 to get 35.

$$TI=\frac{35}{\left(4+7\right)\left(4+3\right)}$$

Add 4 and 7 to get 11.

$$TI=\frac{35}{11\left(4+3\right)}$$

Add 4 and 3 to get 7.

$$TI=\frac{35}{11\times 7}$$

Multiply 11 and 7 to get 77.

$$TI=\frac{35}{77}$$

Reduce the fraction \frac{35}{77} to lowest terms by extracting and canceling out 7.

$$TI=\frac{5}{11}$$

Divide both sides by T.

$$\frac{TI}{T}=\frac{\frac{5}{11}}{T}$$

Dividing by T undoes the multiplication by T.

$$I=\frac{\frac{5}{11}}{T}$$

Divide \frac{5}{11} by T.

$$I=\frac{5}{11T}$$

Solve for T

$$T=\frac{5}{11I}$$

$$I\neq 0$$

Steps for Solving Linear Equation

Multiply 5 and 7 to get 35.

$$TI=\frac{35}{\left(4+7\right)\left(4+3\right)}$$

Add 4 and 7 to get 11.

$$TI=\frac{35}{11\left(4+3\right)}$$

Add 4 and 3 to get 7.

$$TI=\frac{35}{11\times 7}$$

Multiply 11 and 7 to get 77.

$$TI=\frac{35}{77}$$

Reduce the fraction \frac{35}{77} to lowest terms by extracting and canceling out 7.

$$TI=\frac{5}{11}$$

The equation is in standard form.

$$IT=\frac{5}{11}$$

Divide both sides by I.

$$\frac{IT}{I}=\frac{\frac{5}{11}}{I}$$

Dividing by I undoes the multiplication by I.

$$T=\frac{\frac{5}{11}}{I}$$

Divide \frac{5}{11} by I.

$$T=\frac{5}{11I}$$