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Solve for C (complex solution)
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Solve for T (complex solution)
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Solve for C
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Solve for T
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TqC=24q-6q^{2}
The equation is in standard form.
\frac{TqC}{Tq}=\frac{6q\left(4-q\right)}{Tq}
Divide both sides by Tq.
C=\frac{6q\left(4-q\right)}{Tq}
Dividing by Tq undoes the multiplication by Tq.
C=\frac{6\left(4-q\right)}{T}
Divide 6q\left(4-q\right) by Tq.
CqT=24q-6q^{2}
The equation is in standard form.
\frac{CqT}{Cq}=\frac{6q\left(4-q\right)}{Cq}
Divide both sides by Cq.
T=\frac{6q\left(4-q\right)}{Cq}
Dividing by Cq undoes the multiplication by Cq.
T=\frac{6\left(4-q\right)}{C}
Divide 6q\left(4-q\right) by Cq.
TqC=24q-6q^{2}
The equation is in standard form.
\frac{TqC}{Tq}=\frac{6q\left(4-q\right)}{Tq}
Divide both sides by Tq.
C=\frac{6q\left(4-q\right)}{Tq}
Dividing by Tq undoes the multiplication by Tq.
C=\frac{6\left(4-q\right)}{T}
Divide 6q\left(4-q\right) by Tq.
CqT=24q-6q^{2}
The equation is in standard form.
\frac{CqT}{Cq}=\frac{6q\left(4-q\right)}{Cq}
Divide both sides by Cq.
T=\frac{6q\left(4-q\right)}{Cq}
Dividing by Cq undoes the multiplication by Cq.
T=\frac{6\left(4-q\right)}{C}
Divide 6q\left(4-q\right) by Cq.