Solve T7x+12y=16

$$T 7 x + 12 y = 16$$

Solve for T_7 (complex solution)

$$\left\{\begin{matrix}T_{7}=-\frac{4\left(3y-4\right)}{x}\text{, }&x\neq 0\\T_{7}\in \mathrm{C}\text{, }&y=\frac{4}{3}\text{ and }x=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Subtract 12y from both sides.

$$T_{7}x=16-12y$$

The equation is in standard form.

$$xT_{7}=16-12y$$

Divide both sides by x.

$$\frac{xT_{7}}{x}=\frac{16-12y}{x}$$

Dividing by x undoes the multiplication by x.

$$T_{7}=\frac{16-12y}{x}$$

Divide 16-12y by x.

$$T_{7}=\frac{4\left(4-3y\right)}{x}$$

Solve for x (complex solution)

$$\left\{\begin{matrix}x=-\frac{4\left(3y-4\right)}{T_{7}}\text{, }&T_{7}\neq 0\\x\in \mathrm{C}\text{, }&y=\frac{4}{3}\text{ and }T_{7}=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Subtract 12y from both sides.

$$T_{7}x=16-12y$$

Divide both sides by T_{7}.

$$\frac{T_{7}x}{T_{7}}=\frac{16-12y}{T_{7}}$$

Dividing by T_{7} undoes the multiplication by T_{7}.

$$x=\frac{16-12y}{T_{7}}$$

Divide 16-12y by T_{7}.

$$x=\frac{4\left(4-3y\right)}{T_{7}}$$

Solve for T_7

$$\left\{\begin{matrix}T_{7}=-\frac{4\left(3y-4\right)}{x}\text{, }&x\neq 0\\T_{7}\in \mathrm{R}\text{, }&y=\frac{4}{3}\text{ and }x=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Subtract 12y from both sides.

$$T_{7}x=16-12y$$

The equation is in standard form.

$$xT_{7}=16-12y$$

Divide both sides by x.

$$\frac{xT_{7}}{x}=\frac{16-12y}{x}$$

Dividing by x undoes the multiplication by x.

$$T_{7}=\frac{16-12y}{x}$$

Divide 16-12y by x.

$$T_{7}=\frac{4\left(4-3y\right)}{x}$$

Solve for x

$$\left\{\begin{matrix}x=-\frac{4\left(3y-4\right)}{T_{7}}\text{, }&T_{7}\neq 0\\x\in \mathrm{R}\text{, }&y=\frac{4}{3}\text{ and }T_{7}=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Subtract 12y from both sides.

$$T_{7}x=16-12y$$

Divide both sides by T_{7}.

$$\frac{T_{7}x}{T_{7}}=\frac{16-12y}{T_{7}}$$

Dividing by T_{7} undoes the multiplication by T_{7}.

$$x=\frac{16-12y}{T_{7}}$$

Divide 16-12y by T_{7}.

$$x=\frac{4\left(4-3y\right)}{T_{7}}$$