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Solve for T_2
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T_{2}=6a+8b+3
Combine -b and 9b to get 8b.
6a+8b+3=T_{2}
Swap sides so that all variable terms are on the left hand side.
6a+3=T_{2}-8b
Subtract 8b from both sides.
6a=T_{2}-8b-3
Subtract 3 from both sides.
\frac{6a}{6}=\frac{T_{2}-8b-3}{6}
Divide both sides by 6.
a=\frac{T_{2}-8b-3}{6}
Dividing by 6 undoes the multiplication by 6.
a=\frac{T_{2}}{6}-\frac{4b}{3}-\frac{1}{2}
Divide T_{2}-8b-3 by 6.
T_{2}=6a+8b+3
Combine -b and 9b to get 8b.