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Tt=10\cot(\frac{\pi t}{48})-10\cot(\frac{\pi t}{24})
Use the distributive property to multiply 10 by \cot(\frac{\pi t}{48})-\cot(\frac{\pi t}{24}).
tT=10\cot(\frac{\pi t}{48})-10\cot(\frac{\pi t}{24})
The equation is in standard form.
\frac{tT}{t}=\frac{10}{\sin(\frac{\pi t}{24})t}
Divide both sides by t.
T=\frac{10}{\sin(\frac{\pi t}{24})t}
Dividing by t undoes the multiplication by t.
T=\frac{10}{t\sin(\frac{\pi t}{24})}
Divide \frac{10}{\sin(\frac{\pi t}{24})} by t.