Solve T^2=50

$$T ^ { 2 } = 50$$

Solve for T

$$T=5\sqrt{2}\approx 7.071067812$$

$$T=-5\sqrt{2}\approx -7.071067812$$

Steps by Finding Square Root

Take the square root of both sides of the equation.

$$T=5\sqrt{2} T=-5\sqrt{2}$$

Steps Using the Quadratic Formula

Subtract 50 from both sides.

$$T^{2}-50=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -50 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$T=\frac{0±\sqrt{0^{2}-4\left(-50\right)}}{2}$$

Square 0.

$$T=\frac{0±\sqrt{-4\left(-50\right)}}{2}$$

Multiply -4 times -50.

$$T=\frac{0±\sqrt{200}}{2}$$

Take the square root of 200.

$$T=\frac{0±10\sqrt{2}}{2}$$

Now solve the equation T=\frac{0±10\sqrt{2}}{2} when ± is plus.

$$T=5\sqrt{2}$$

Now solve the equation T=\frac{0±10\sqrt{2}}{2} when ± is minus.

$$T=-5\sqrt{2}$$

The equation is now solved.

$$T=5\sqrt{2} T=-5\sqrt{2}$$