Solve T=2pisqrt{l/9.8}quad[2]

$$T = 2 \pi \sqrt { \frac { l } { 9.8 } } \quad [ 2 ]$$

Solve for l

$$l=\frac{49\times \left(\frac{T}{\pi }\right)^{2}}{80}$$

$$T\geq 0$$

Steps for Solving Radical Equations

Multiply 2 and 2 to get 4.

$$T=4\pi \sqrt{\frac{l}{9.8}}$$

Swap sides so that all variable terms are on the left hand side.

$$4\pi \sqrt{\frac{l}{9.8}}=T$$

Divide both sides by 4\pi .

$$\frac{4\pi \sqrt{\frac{5}{49}l}}{4\pi }=\frac{T}{4\pi }$$

Dividing by 4\pi undoes the multiplication by 4\pi .

$$\sqrt{\frac{5}{49}l}=\frac{T}{4\pi }$$

Square both sides of the equation.

$$\frac{5}{49}l=\frac{T^{2}}{16\pi ^{2}}$$

Divide both sides of the equation by \frac{5}{49}, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{\frac{5}{49}l}{\frac{5}{49}}=\frac{T^{2}}{\frac{5}{49}\times 16\pi ^{2}}$$

Dividing by \frac{5}{49} undoes the multiplication by \frac{5}{49}.

$$l=\frac{T^{2}}{\frac{5}{49}\times 16\pi ^{2}}$$

Divide \frac{T^{2}}{16\pi ^{2}} by \frac{5}{49} by multiplying \frac{T^{2}}{16\pi ^{2}} by the reciprocal of \frac{5}{49}.

$$l=\frac{49T^{2}}{80\pi ^{2}}$$

Solve for T

$$T=\frac{4\pi \sqrt{5l}}{7}$$

$$l\geq 0$$