Solve Sd_{1}=40x_{1}y+40x_{1}5+35x_{1}4x_{1}6+50x_{1}2*96

$$S d _ { 1 } = 40 x _ { 1 } y + 40 x _ { 1 } 5 + 35 x _ { 1 } 4 x _ { 1 } 6 + 50 x _ { 1 } 2 \times 96$$

Solve for S (complex solution)

$$\left\{\begin{matrix}S=\frac{40x_{1}\left(21x_{1}+y+245\right)}{d_{1}}\text{, }&d_{1}\neq 0\\S\in \mathrm{C}\text{, }&\left(x_{1}=0\text{ or }x_{1}=-\frac{y}{21}-\frac{35}{3}\right)\text{ and }d_{1}=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Multiply x_{1} and x_{1} to get x_{1}^{2}.

$$Sd_{1}=40x_{1}y+40x_{1}\times 5+35x_{1}^{2}\times 4\times 6+50x_{1}\times 2\times 96$$

Multiply 40 and 5 to get 200.

$$Sd_{1}=40x_{1}y+200x_{1}+35x_{1}^{2}\times 4\times 6+50x_{1}\times 2\times 96$$

Multiply 35 and 4 to get 140.

$$Sd_{1}=40x_{1}y+200x_{1}+140x_{1}^{2}\times 6+50x_{1}\times 2\times 96$$

Multiply 140 and 6 to get 840.

$$Sd_{1}=40x_{1}y+200x_{1}+840x_{1}^{2}+50x_{1}\times 2\times 96$$

Multiply 50 and 2 to get 100.

$$Sd_{1}=40x_{1}y+200x_{1}+840x_{1}^{2}+100x_{1}\times 96$$

Multiply 100 and 96 to get 9600.

$$Sd_{1}=40x_{1}y+200x_{1}+840x_{1}^{2}+9600x_{1}$$

Combine 200x_{1} and 9600x_{1} to get 9800x_{1}.

$$Sd_{1}=40x_{1}y+9800x_{1}+840x_{1}^{2}$$

The equation is in standard form.

$$d_{1}S=840x_{1}^{2}+40x_{1}y+9800x_{1}$$

Divide both sides by d_{1}.

$$\frac{d_{1}S}{d_{1}}=\frac{40x_{1}\left(21x_{1}+y+245\right)}{d_{1}}$$

Dividing by d_{1} undoes the multiplication by d_{1}.

$$S=\frac{40x_{1}\left(21x_{1}+y+245\right)}{d_{1}}$$

Solve for d_1 (complex solution)

$$\left\{\begin{matrix}d_{1}=\frac{40x_{1}\left(21x_{1}+y+245\right)}{S}\text{, }&S\neq 0\\d_{1}\in \mathrm{C}\text{, }&\left(x_{1}=0\text{ or }x_{1}=-\frac{y}{21}-\frac{35}{3}\right)\text{ and }S=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Multiply x_{1} and x_{1} to get x_{1}^{2}.

$$Sd_{1}=40x_{1}y+40x_{1}\times 5+35x_{1}^{2}\times 4\times 6+50x_{1}\times 2\times 96$$

Multiply 40 and 5 to get 200.

$$Sd_{1}=40x_{1}y+200x_{1}+35x_{1}^{2}\times 4\times 6+50x_{1}\times 2\times 96$$

Multiply 35 and 4 to get 140.

$$Sd_{1}=40x_{1}y+200x_{1}+140x_{1}^{2}\times 6+50x_{1}\times 2\times 96$$

Multiply 140 and 6 to get 840.

$$Sd_{1}=40x_{1}y+200x_{1}+840x_{1}^{2}+50x_{1}\times 2\times 96$$

Multiply 50 and 2 to get 100.

$$Sd_{1}=40x_{1}y+200x_{1}+840x_{1}^{2}+100x_{1}\times 96$$

Multiply 100 and 96 to get 9600.

$$Sd_{1}=40x_{1}y+200x_{1}+840x_{1}^{2}+9600x_{1}$$

Combine 200x_{1} and 9600x_{1} to get 9800x_{1}.

$$Sd_{1}=40x_{1}y+9800x_{1}+840x_{1}^{2}$$

The equation is in standard form.

$$Sd_{1}=840x_{1}^{2}+40x_{1}y+9800x_{1}$$

Divide both sides by S.

$$\frac{Sd_{1}}{S}=\frac{40x_{1}\left(21x_{1}+y+245\right)}{S}$$

Dividing by S undoes the multiplication by S.

$$d_{1}=\frac{40x_{1}\left(21x_{1}+y+245\right)}{S}$$

Solve for S

$$\left\{\begin{matrix}S=\frac{40x_{1}\left(21x_{1}+y+245\right)}{d_{1}}\text{, }&d_{1}\neq 0\\S\in \mathrm{R}\text{, }&\left(x_{1}=0\text{ or }x_{1}=-\frac{y}{21}-\frac{35}{3}\right)\text{ and }d_{1}=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Multiply x_{1} and x_{1} to get x_{1}^{2}.

$$Sd_{1}=40x_{1}y+40x_{1}\times 5+35x_{1}^{2}\times 4\times 6+50x_{1}\times 2\times 96$$

Multiply 40 and 5 to get 200.

$$Sd_{1}=40x_{1}y+200x_{1}+35x_{1}^{2}\times 4\times 6+50x_{1}\times 2\times 96$$

Multiply 35 and 4 to get 140.

$$Sd_{1}=40x_{1}y+200x_{1}+140x_{1}^{2}\times 6+50x_{1}\times 2\times 96$$

Multiply 140 and 6 to get 840.

$$Sd_{1}=40x_{1}y+200x_{1}+840x_{1}^{2}+50x_{1}\times 2\times 96$$

Multiply 50 and 2 to get 100.

$$Sd_{1}=40x_{1}y+200x_{1}+840x_{1}^{2}+100x_{1}\times 96$$

Multiply 100 and 96 to get 9600.

$$Sd_{1}=40x_{1}y+200x_{1}+840x_{1}^{2}+9600x_{1}$$

Combine 200x_{1} and 9600x_{1} to get 9800x_{1}.

$$Sd_{1}=40x_{1}y+9800x_{1}+840x_{1}^{2}$$

The equation is in standard form.

$$d_{1}S=840x_{1}^{2}+40x_{1}y+9800x_{1}$$

Divide both sides by d_{1}.

$$\frac{d_{1}S}{d_{1}}=\frac{40x_{1}\left(21x_{1}+y+245\right)}{d_{1}}$$

Dividing by d_{1} undoes the multiplication by d_{1}.

$$S=\frac{40x_{1}\left(21x_{1}+y+245\right)}{d_{1}}$$

Solve for d_1

$$\left\{\begin{matrix}d_{1}=\frac{40x_{1}\left(21x_{1}+y+245\right)}{S}\text{, }&S\neq 0\\d_{1}\in \mathrm{R}\text{, }&\left(x_{1}=0\text{ or }x_{1}=-\frac{y}{21}-\frac{35}{3}\right)\text{ and }S=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Multiply x_{1} and x_{1} to get x_{1}^{2}.

$$Sd_{1}=40x_{1}y+40x_{1}\times 5+35x_{1}^{2}\times 4\times 6+50x_{1}\times 2\times 96$$

Multiply 40 and 5 to get 200.

$$Sd_{1}=40x_{1}y+200x_{1}+35x_{1}^{2}\times 4\times 6+50x_{1}\times 2\times 96$$

Multiply 35 and 4 to get 140.

$$Sd_{1}=40x_{1}y+200x_{1}+140x_{1}^{2}\times 6+50x_{1}\times 2\times 96$$

Multiply 140 and 6 to get 840.

$$Sd_{1}=40x_{1}y+200x_{1}+840x_{1}^{2}+50x_{1}\times 2\times 96$$

Multiply 50 and 2 to get 100.

$$Sd_{1}=40x_{1}y+200x_{1}+840x_{1}^{2}+100x_{1}\times 96$$

Multiply 100 and 96 to get 9600.

$$Sd_{1}=40x_{1}y+200x_{1}+840x_{1}^{2}+9600x_{1}$$

Combine 200x_{1} and 9600x_{1} to get 9800x_{1}.

$$Sd_{1}=40x_{1}y+9800x_{1}+840x_{1}^{2}$$

The equation is in standard form.

$$Sd_{1}=840x_{1}^{2}+40x_{1}y+9800x_{1}$$

Divide both sides by S.

$$\frac{Sd_{1}}{S}=\frac{40x_{1}\left(21x_{1}+y+245\right)}{S}$$

Dividing by S undoes the multiplication by S.

$$d_{1}=\frac{40x_{1}\left(21x_{1}+y+245\right)}{S}$$