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Solve for S
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S=\frac{1}{7}r+\frac{1}{7}p
Divide each term of r+p by 7 to get \frac{1}{7}r+\frac{1}{7}p.
\frac{1}{7}r+\frac{1}{7}p=S
Swap sides so that all variable terms are on the left hand side.
\frac{1}{7}p=S-\frac{1}{7}r
Subtract \frac{1}{7}r from both sides.
\frac{1}{7}p=-\frac{r}{7}+S
The equation is in standard form.
\frac{\frac{1}{7}p}{\frac{1}{7}}=\frac{-\frac{r}{7}+S}{\frac{1}{7}}
Multiply both sides by 7.
p=\frac{-\frac{r}{7}+S}{\frac{1}{7}}
Dividing by \frac{1}{7} undoes the multiplication by \frac{1}{7}.
p=7S-r
Divide S-\frac{r}{7} by \frac{1}{7} by multiplying S-\frac{r}{7} by the reciprocal of \frac{1}{7}.
S=\frac{1}{7}r+\frac{1}{7}p
Divide each term of r+p by 7 to get \frac{1}{7}r+\frac{1}{7}p.