Solve R_{T}=1/frac{1{4}+1/8+1/6}

$$R _ { T } = \frac { 1 } { \frac { 1 } { 4 } + \frac { 1 } { 8 } + \frac { 1 } { 6 } }$$

Solve for R_T

$$R_{T} = \frac{24}{13} = 1\frac{11}{13} \approx 1.846153846$$

Steps for Solving Linear Equation

Least common multiple of 4 and 8 is 8. Convert \frac{1}{4} and \frac{1}{8} to fractions with denominator 8.

$$R_{T}=\frac{1}{\frac{2}{8}+\frac{1}{8}+\frac{1}{6}}$$

Since \frac{2}{8} and \frac{1}{8} have the same denominator, add them by adding their numerators.

$$R_{T}=\frac{1}{\frac{2+1}{8}+\frac{1}{6}}$$

Add 2 and 1 to get 3.

$$R_{T}=\frac{1}{\frac{3}{8}+\frac{1}{6}}$$

Least common multiple of 8 and 6 is 24. Convert \frac{3}{8} and \frac{1}{6} to fractions with denominator 24.

$$R_{T}=\frac{1}{\frac{9}{24}+\frac{4}{24}}$$

Since \frac{9}{24} and \frac{4}{24} have the same denominator, add them by adding their numerators.

$$R_{T}=\frac{1}{\frac{9+4}{24}}$$

Add 9 and 4 to get 13.

$$R_{T}=\frac{1}{\frac{13}{24}}$$

Divide 1 by \frac{13}{24} by multiplying 1 by the reciprocal of \frac{13}{24}.

$$R_{T}=1\times \frac{24}{13}$$

Multiply 1 and \frac{24}{13} to get \frac{24}{13}.

$$R_{T}=\frac{24}{13}$$

Assign R_T

$$R_{T}≔\frac{24}{13}$$