R M 3 = 20 \%
Solve for M_3
M_{3}=\frac{1}{5R}
R\neq 0
Solve for R
R=\frac{1}{5M_{3}}
M_{3}\neq 0
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RM_{3}=\frac{1}{5}
Reduce the fraction \frac{20}{100} to lowest terms by extracting and canceling out 20.
\frac{RM_{3}}{R}=\frac{\frac{1}{5}}{R}
Divide both sides by R.
M_{3}=\frac{\frac{1}{5}}{R}
Dividing by R undoes the multiplication by R.
M_{3}=\frac{1}{5R}
Divide \frac{1}{5} by R.
RM_{3}=\frac{1}{5}
Reduce the fraction \frac{20}{100} to lowest terms by extracting and canceling out 20.
M_{3}R=\frac{1}{5}
The equation is in standard form.
\frac{M_{3}R}{M_{3}}=\frac{\frac{1}{5}}{M_{3}}
Divide both sides by M_{3}.
R=\frac{\frac{1}{5}}{M_{3}}
Dividing by M_{3} undoes the multiplication by M_{3}.
R=\frac{1}{5M_{3}}
Divide \frac{1}{5} by M_{3}.
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