Solve R(x)=6x-C(x)=70+4x

$$R ( x ) = 6 x - C ( x ) = 70 + 4 x$$

Solve for C

$$C=2-\frac{70}{x}$$

$$x\neq 0$$

Steps for Solving Linear Equation

Subtract 6x from both sides.

$$-Cx=70+4x-6x$$

Combine 4x and -6x to get -2x.

$$-Cx=70-2x$$

The equation is in standard form.

$$\left(-x\right)C=70-2x$$

Divide both sides by -x.

$$\frac{\left(-x\right)C}{-x}=\frac{70-2x}{-x}$$

Dividing by -x undoes the multiplication by -x.

$$C=\frac{70-2x}{-x}$$

Divide 70-2x by -x.

$$C=2-\frac{70}{x}$$

Solve for x

$$x=\frac{70}{2-C}$$

$$C\neq 2$$

Steps for Solving Linear Equation

Subtract 4x from both sides.

$$6x-Cx-4x=70$$

Combine 6x and -4x to get 2x.

$$2x-Cx=70$$

Combine all terms containing x.

$$\left(2-C\right)x=70$$

Divide both sides by 2-C.

$$\frac{\left(2-C\right)x}{2-C}=\frac{70}{2-C}$$

Dividing by 2-C undoes the multiplication by 2-C.

$$x=\frac{70}{2-C}$$