Solve R=A+V^2/B

$$R = A + \frac { V ^ { 2 } } { B }$$

Solve for A

$$A=-\frac{V^{2}}{B}+R$$

$$B\neq 0$$

Steps for Solving Linear Equation

Multiply both sides of the equation by B.

$$RB=BA+V^{2}$$

Swap sides so that all variable terms are on the left hand side.

$$BA+V^{2}=RB$$

Subtract V^{2} from both sides.

$$BA=RB-V^{2}$$

The equation is in standard form.

$$BA=BR-V^{2}$$

Divide both sides by B.

$$\frac{BA}{B}=\frac{BR-V^{2}}{B}$$

Dividing by B undoes the multiplication by B.

$$A=\frac{BR-V^{2}}{B}$$

Divide BR-V^{2} by B.

$$A=-\frac{V^{2}}{B}+R$$

Solve for B

$$\left\{\begin{matrix}B=-\frac{V^{2}}{A-R}\text{, }&V\neq 0\text{ and }R\neq A\\B\neq 0\text{, }&R=A\text{ and }V=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Variable B cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by B.

$$RB=BA+V^{2}$$

Subtract BA from both sides.

$$RB-BA=V^{2}$$

Combine all terms containing B.

$$\left(R-A\right)B=V^{2}$$

Divide both sides by R-A.

$$\frac{\left(R-A\right)B}{R-A}=\frac{V^{2}}{R-A}$$

Dividing by R-A undoes the multiplication by R-A.

$$B=\frac{V^{2}}{R-A}$$

Variable B cannot be equal to 0.

$$B=\frac{V^{2}}{R-A}\text{, }B\neq 0$$