Solve for D
D=3R+T
Solve for R
R=\frac{D-T}{3}
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R=\frac{1}{3}D-\frac{1}{3}T
Divide each term of D-T by 3 to get \frac{1}{3}D-\frac{1}{3}T.
\frac{1}{3}D-\frac{1}{3}T=R
Swap sides so that all variable terms are on the left hand side.
\frac{1}{3}D=R+\frac{1}{3}T
Add \frac{1}{3}T to both sides.
\frac{1}{3}D=\frac{T}{3}+R
The equation is in standard form.
\frac{\frac{1}{3}D}{\frac{1}{3}}=\frac{\frac{T}{3}+R}{\frac{1}{3}}
Multiply both sides by 3.
D=\frac{\frac{T}{3}+R}{\frac{1}{3}}
Dividing by \frac{1}{3} undoes the multiplication by \frac{1}{3}.
D=3R+T
Divide R+\frac{T}{3} by \frac{1}{3} by multiplying R+\frac{T}{3} by the reciprocal of \frac{1}{3}.
R=\frac{1}{3}D-\frac{1}{3}T
Divide each term of D-T by 3 to get \frac{1}{3}D-\frac{1}{3}T.
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